python实现mask矩阵示例(根据列表所给元素)

行和列的位置都在以下三个列表中的一列中，则对应位置为1，其余位置全为0

​ ——[7-56,239-327,438-454,522-556,574-586]

​ ——[57-85,96-112,221-238]

​ ——[113-220,328-437,455-521,557-573]

代码实现

def generateMaskBasedOnDom(dom_path, length): ''' :param dom_path: this is a file path, which contains the following information: [7-56,239-327,438-454,522-556,574-586][57-85,96-112,221-238][113-220,328-437,455-521,557-573] each [...] means one domain :param length: this is the length of this protein :return: the mask matrix with size length x length, 1 means inner domain residue pair, otherwise 0 ''' # 读取文件 with open(dom_path, 'r', encoding='utf-8') as file: contents = file.readlines() # 获得mask位置数据 list0 = [] list1 = [] list2 = [] for list_idx, content in enumerate(contents): num_range_list = content.strip()[1:-1].split(',') for num_range in num_range_list: start_num = int(num_range.split('-')[0]) end_num = int(num_range.split('-')[1]) for num in range(start_num, end_num+1):if list_idx == 0: list0.append(num)elif list_idx == 1: list1.append(num)else: list2.append(num) mask = np.zeros((length, length)) # 遍历矩阵每个元素 for row in range(mask.shape[0]): for col in range(mask.shape[1]): if (row in list0 and col in list0) or (row in list1 and col in list1) or (row in list2 and col in list2):mask[row][col] = 1 return maskif __name__ == '__main__': # if no dom file ,please get dom file first with open('dom.txt', 'w', encoding='utf-8') as f: f.write('[7-56,239-327,438-454,522-556,574-586]' + 'n' + '[57-85,96-112,221-238]' + 'n' + '[113-220,328-437,455-521,557-573]') file_path = './dom.txt' protein_length = 1000 # mask_matrix size mask_matrix = generateMaskBasedOnDom(file_path, protein_length) print('*************Generate Mask Matrix Successful!*************') # 随机测试几组 print(mask_matrix[7][56]) # 1 print(mask_matrix[7][239]) # 1 print(mask_matrix[8][57]) # 0 print(mask_matrix[57][95]) # 0 print(mask_matrix[113][573]) # 1

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