java返回java.lang.NumberFormatException异常

问题描述

代码如下,其中getX()成功有返回结果,getY()却报异常.

public class AddressUtilDemo { public static void main(String[] args){AddressUtil AddressUtil = new AddressUtil();AddressUtil.setAddress('3454.234,24l.432');System.out.println(AddressUtil.getX());System.out.println(AddressUtil.getY()); }}class AddressUtil { private String address; public AddressUtil(){} public AddressUtil(String address){if(address.indexOf(',')>0){ this.address = address;} } public Double getX(){String string = address.substring(0, address.indexOf(',')) ;return Double.parseDouble(string); } public Double getY(){String string = address.substring((address.indexOf(',')+1));return Double.parseDouble(string); } public String getAddress() {return address; } public void setAddress(String address) {this.address = address.trim(); }}

试过string.trim()等方法都无效.debug看到的string确实是预期中的数值.以下是异常信息:

Exception in thread 'main' java.lang.NumberFormatException: For input string: '24l.432'

问题解答

你应该学会调试,看看getY中的string就知道问题了

24l.43224后们是 L，不是 1

骚年，你main函数里setAddress的是3454.234,24l.432（24L，是L不是1），所以y是错的，转化失败了，建议编辑器字体用Source Code Pro 还能看的出来