mysql - 字符串根据字典替换

问题描述

源表:

字典表:

期望将源表的数值根据字典表进行替换,目标结果如下:

尝试过用replace函数,但是只能单个替换.(注:其他由于是逗号分隔,字典表id可1~100,需要用正则表达式替换,否则12会被id1,2拆开)

问题解答

自己写的递归函数

DELIMITER $$DROP FUNCTION IF EXISTS junk.StringReplaceSplit $$CREATE FUNCTION junk.StringReplaceSplit (v_str VARCHAR(1024), v_split VARCHAR(1024)) RETURNS VARCHAR(1024)DETERMINISTICBEGIN  DECLARE rv VARCHAR(1024);  DECLARE splist_count INT;  DECLARE i INT;  DROP TEMPORARY TABLE IF EXISTS tmp_table;  CREATE TEMPORARY TABLE tmp_table(v_key VARCHAR(100));   SET i = 1;  set splist_count = (length(v_str)-length(replace(v_str, v_split,’’)))/length(v_split)+1;  WHILE i <= splist_count DO    INSERT INTO tmp_table      SELECT REPLACE(substring(substring_index(v_str, v_split, i),                     length(substring_index(v_str, v_split, i-1)) + 1),                      v_split, ’’);    SET i = i + 1;  END WHILE;  SELECT replace(group_concat(ifnull(wordlist.word, tmp_table.v_key)), ’,’, v_split) INTO rv    from tmp_table    LEFT JOIN wordlist on wordlist.id=tmp_table.v_key;  RETURN rv;END $$DELIMITER ;

效果:源表

mysql> select * from teststring;+----+----------------------------+| id | String |+----+----------------------------+| 1 | 1,2,3,4,5 || 2 | 4,5,7,8,84 || 3 | key,23,344,12,3,9,34,3,1,3 |+----+----------------------------+3 rows in set (0.00 sec)

字典表

mysql> select * from wordlist;+----+-------+| id | word |+----+-------+| 1 | one || 2 | two || 3 | three || 4 | four || 5 | five || 7 | six || 8 | eight || 9 | nine || 10 | ten |+----+-------+9 rows in set (0.00 sec)

示例:

mysql> SELECT id, StringReplaceSplit(String,’,’) transform from teststring ;+----+---------------------------------------------+| id | transform |+----+---------------------------------------------+| 1 | one,two,three,four,five || 2 | four,five,six,eight,84 || 3 | key,23,344,12,three,nine,34,three,one,three |+----+---------------------------------------------+3 rows in set (0.04 sec)

函数有待优化.